Есть форма html
<FORM action="php/vugryz.php" method=post>
<b> Выбрать автомобиль</b>
<select size="3" multiple name ="car">
<option disabled>Выберите номер автомобиля</option>
<option value = "">039-63</option>
<option value = "1">039-64</option>
<option value = "2">59-47</option>
<option value = "3">42-83</option>
<option value = "4">39-65</option>
<option value = "5">15-62</option>
<option value = "6">39-67</option>
<option value = "7">39-66</option>
<option value = "8">09-56</option>
<option value = "9">81-07</option>
</select>
<b> Выбрать водителя</b>
<select name = "driver">
<option value = "">выбрать</option>
<option value = "1">...</option>
<option value = "2">...</option>
<option value = "3">...</option>
<option value = "4">...</option>
<option value = "5">...</option>
<option value = "6">...</option>
<option value = "7">...</option>
<option value = "8">...</option>
<option value = "9">...</option>
<option value = "10">...</option>
<option value = "11">...</option>
<option value = "12">...</option>
<option value = "13">...</option>
</select>
</select>
<b> Выбрать дату</b>
<label for="data" > </label>
<input type = "date" name='data' size="50"/></br>
</select>
<INPUT type=submit name="Поиск" value=" РАСЧЕТ ">
</FORM>
Как правильно оформить vugryz.php ???
[/code]
<?php
require_once ('bd_conect.php'); //можно использовать include //
$result = mysql_query("SELECT * FROM GPS_table ORDER BY name DESC ",$connect);
mysql_query($insert_sql)
or die(mysql_error());
?>
[code]
СТруктура бд :
