Вот код
$link=mysql_connect("localhost",'nevonn23-4',"pppppp");
mysql_select_db("nevonn23-4");
$login=$_POST['login'];
$result=mysql_query("SELECT * FROM igroki, WHERE login='$login'",$link);
$connect=mysql_fetch_array($result, MYSQL_ASSOC)
пишет
Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/users/n/nevonn23-4/domains/nevonn23-4.myjino.ru/login.php on line 11
помогите, што делать?