<?php

function db_connect()
{
    $host = 'localhost'; 
    $user = 'root';
    $password = '';
    $db = 'elite_shop';

    $connection = mysql_connect($host, $user, $password);
    if (!conection || !mysql_select_db($db, $connection)) {
        return false;
    }
    return $connection;

}


function db_result_to_array()
{
    $res_array = array();

    $count = 0;

    while ($row = mysql_fetch_array($result)) { // тут ошибка
        $res_array[$count] = $row;
        $count++;
    }
    return $res_array;

}

function get_products()
{
    db_connect();

    $query = "SELECT title FROM products";

    $result = mysql_query($query);

    $result = db_result_to_array($result);

    return $result;
}



?>


<?
$products = get_products();
foreach($products as $item) :?>

<table align="center" cellpadding="0" class="product" border="0">
<tr>
<td valign="top">
<div><a href="#"<img src="img/<? $item['image']?>" alt="" /></a></div>
<div class="description">
<div class="product-name"><a href="#"><? $item['title']?></a></div>
<div class="product-price"> <? $item['price']?></div>
</div>
</td>
</tr>
</table>

<?endforeach;?>

Вроде все верно, но выдает ошибку

Warning: mysql_fetch_array() expects parameter 1 to be resource, integer given in Z:\home\mysite.ru\www\db_fns.php on line 28

Помогите разобраться.