Доброй ночи!
выскакивает при постоянном обновлении сайта.

Warning: mysql_connect() [function.mysql-connect]: User z26244 already has more than 'max_user_connections' active connections in MySql.php on line 6
Error: Can't connect to MySQL!
Warning: mysql_close(): no MySQL-Link resource supplied in MySql.php on line 33

MySql.php on line 6
это

    $result=mysql_connect(DB_HOST, DB_NAME, DB_PASS) or die("Error: Can't connect to MySQL!");

MySql.php on line 33
это

         mysql_close();

вот весь класс

<?php
header('Content-Type: text/html; charset=utf8');
include_once (ROOT_DIR.'global.php');
Class MySQL{ 
     public function __construct(){
        $result=mysql_connect(DB_HOST, DB_NAME, DB_PASS) or die("Error: Can't connect to MySQL!");
        @mysql_query ("set character_set_client='".CHARACTER."'");
        @mysql_query ("set character_set_results='".CHARACTER."'");
        @mysql_query ("set collation_connection='".CHARACTER_FULL."'");    
        $result.=mysql_select_db(DB_NAME) or die("Error: There is no database with the same name!");
        mysql_query("SET NAMES '".CHARACTER."'"); 
        return $result;
    }
    
    static public function query($query,$r= null,$mf =null){
    $result=mysql_query($query) or die(mysql_error());
        if(!$r or $r=='res'){
        return $result;
        }elseif($r=='row' && $mf == 'array'){
          $row = mysql_fetch_array($result);
        return $row;   
        }elseif($r=='row' && $mf == 'cont'){
        $row = mysql_fetch_assoc($result);
        return count($row);   
        }elseif($r=='row' && $mf == 'assoc'){
        $row =  mysql_fetch_assoc($result);
        return $row;    
        }

    }
    
     public function __destruct(){
         mysql_close();
     } 
}

?> 

возникает вопрос, как исправить?