Есть два очень похожих запроса с отличием в две строчки:

$info = "SELECT ".$tname." AS tn, t1.teamid, ".$ncountry."  as cn, c1.flag, ".$tcity." as cityn 
    FROM team AS t1
    INNER JOIN city AS c2 ON ".$tname." LIKE '$queryString%' and t1.cityid=c2.cityid					         
    INNER JOIN country AS c1 ON c2.countryid=c1.countryid
    ORDER BY ".$tname."";

...и

$info = "SELECT ".$tname." AS tn, t1.teamid, ".$ncountry."  as cn, c1.flag 
    FROM team AS t1
    INNER JOIN country AS c1 ON ".$tname." LIKE '$queryString%' and t1.cityid=0 and ".$tname."=".$ncountry."
    ORDER BY ".$tname."";

Я решил немного подсократить код:

$qfilds="SELECT ".$tname." AS tn, t1.teamid, ".$ncountry."  as cn, c1.flag, ".$tcity." as cityn";
$qinner="INNER JOIN city AS c2 ON ".$tname." LIKE '$queryString%' and t1.cityid=c2.cityid

...И

$qfilds="SELECT ".$tname." AS tn, t1.teamid, ".$ncountry."  as cn, c1.flag";
$qinner="INNER JOIN country AS c1 ON ".$tname." LIKE '$queryString%' and t1.cityid=0 and ".$tname."=".$ncountry."";

Вставляя это добро в составную строку запроса:

$info = $qfilds. "FROM team AS t1 ".$qinner." ORDER BY ".$tname."";

Но так не работает, похоже где-то промахнулся с кавычками, но никак не могу понять где(((