Выводит ошибку: Parse error: syntax error, unexpected T_LNUMBER, expecting ',' or ';

<?php
	$sql = mysql_query("SELECT * FROM all") or die(mysql_error());
	while($res = mysql_fetch_array($sql)){
	echo"
            <td width="56"><img width=\"56\" height=\"56\" src=\"" .$res["icon"] ."\"></td>
            <td><div class=\"post_title_page\"><a href="/"><img alt=\"home\" src=\"" .$res["confirm"] ."\">" .$res["name"] ."</a></div> <div class=\"post_info_page\"></div></td>
        </tr>
    </table>
    <table cellpadding="0" cellspacing="0" border="0" align="center">
        <tr valign="top">
           
            <td><a href=\"" .$res["download"] ."\"> class=\"download\"></a></td>
        </tr>
    </table>
</div>