$sql = mysql_query ("INSERT INTO results (date, point_cod_1c, user_id) VALUES ($dat, $point[code_1c], $user[ID])");
Спустя 2 минуты, 46 секунд (20.04.2011 - 12:54) ZSH написал(а):
$id = mysql_insert_id();
$sql = mysql_query ("INSERT INTO results (date, point_cod_1c, user_id) VALUES ($dat, $point[code_1c], $user[ID])");
$id = mysql_insert_id();