SELECT c.name, k.name FROM links 
LEFT JOIN c ON c.id=l.id_c
LEFT JOIN k ON k.id=l.id_k
WHERE COUNT(DISTINCT k.name)>1

for (i=1; i < $a; i++) 
{
   $sql = mysql_query ("SELECT * FROM links WHERE nast=1 AND `churst_id` = '".$a."'",$db);
   if (mysql_num_rows($pages) > 1)  {"ТУТ ИХ БОЛЬШЕ +)";}
}

SELECT dbcklink.churchid,  COUNT( dbcklink.churchid) AS kol FROM dbcklink
 where  nast ='1' group by dbcklink.churchid HAVING COUNT( dbcklink.churchid)>1

SELECT * FROM links
while($myrow)
{
   INSERT INTO священники 
   SET храм_ид и настоятель_ид
   WHERE id = $myrow['священник_id']
}